Using the known distance across the WTC tower (208 feet) I was able to gauge the screen of this video to scale. Using the step forward feature of my DVD player each step forward is one frame, and it moves forward in time at 24 frames per second, and so I have known distances and known time. This makes it possible to estimate the time and distance traveled by an object between 2 known points. I kept track of the distance by adhering post it notes to my screen. See the method for used for estimating distances http://www.v911t.org/MakingScale.php In this screen shot I use the video controller to mark the exact spot where the tip of the antenna finally disappears. The starting point shows the antenna already in motion, I had to do that, otherwise the top of the antenna would not show up in the screen capture. Anyone with a DVD player, paint, Dreamweaver, and a way to crop pictures should be able to reproduce this precision analysis of the velocity of the collapse. See the method for used for estimating distances http://www.v911t.org/MakingScale.php

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At time t = s after being dropped, the speed is vy = m/s = ft/s , The distance from the starting point will be y = m= ft

So we can see and measure the time it took for the antenna to move 231 feet with very good precision. We can conclude with great confidence that the WTC tower is falling with at least no resistance, and in fact may be being pulled down by a force in addition to gravity. As you can see in the calculations below an object falling in a vacuum would travel 100.4750 feet in 2.5 seconds. Here we have a descrepency that disagrees with the laws of gravity, the antenna falls 231 feet, and in a vaccum with no resistance it would have fallen 100.4750.

At time t = s after being dropped, the speed is vy = m/s = ft/s , The distance from the starting point will be y = m= ft

See the method for used for estimating distances http://www.v911t.org/MakingScale.php

The Calculators will not be functional here you will have to go to the site 
 http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html

It is a drag, but calculating fall time in atmosphere is much more complicated than in a vacuum, but here we estimate the fall time of an apple based on 3 Coefficients of Drag. Fairly small changes in the CD have a fairly drastic effect on fall time.
CD for a sphere has a huge range from .07 to .5, an apple is not a sphere, so an educated guess is a CD of .7

CD @ .07 dropped from 610 feet = TV of 290.274 ft/sec = fall time of 6.1599 secs
CD @ .5 dropped from _610 feet = TV of 108.61 ft/sec_ = fall time of 7.3043 secs
CD @ .7 dropped from _610 feet = TV of 91.792 ft/s ___= fall time of 8.0770 secs

See this video, a study of the fall of WTC 7 http://www.v911t.org/911Clips.php


Apples are not perfect spheres and so without wind tunnel testing one could estimate that .5 is closer to the CD than .07, or if we dropped an apple from 610 feet we could back our way in to the CD with algebra if we could observe the fall time. My guess is that the CD for an apple is more like .7 depending on the apple. Using a of .7 CD dropped from __610 feet = TV of 91.792 ft/sec
Conclusion: Call in the Myth Busters

See the method for used for estimating distances http://www.v911t.org/MakingScale.php
The original 7 World Trade Center was a 47-story building, designed by Emery Roth & Sons, with a red granite façade. The building was 610 feet (186 m) tall, with a trapezoid-shaped footprint that was 330 ft (101 m) long and 140 ft (43 m) wide.[1][2] Tishman Realty & Construction managed construction of the building, which began in 1984.[1] In March 1987, the building opened, to become the seventh structure of the World Trade Center. http://en.wikipedia.org/wiki/7_World_Trade_Center
So we see that 345 feet is covered in 5.125, and 375 feet is covered in 5.33 seconds. Below are the calculations of distance covered in freefall in 5.125 and 5.33 seconds.
Freefall at 5.125 secs = ft and Freefall at 5.33 secs. = ft so it is safe to say that WTC 7 dropped at or very near freefall velocity. 422 v 345 (81.75%), is 77 feet more distance traveled. 456 v 375 (82.23%) freefall is 81 ft more distance traveled, so we can see based upon the gain of the % comparison that as the fall continues the building is getting closer to freefall velocity, not further away, in other words resistance is decreasing. WTC 7 is somehow accelerating at an increasing rate. See the method for used for estimating distances http://www.v911t.org/MakingScale.php
At time t = s after being dropped, the speed is vy = m/s = ft/s , The distance from the starting point will be y = m= ft   At time t = s after being dropped, the speed is vy = m/s = ft/s , The distance from the starting point will be y = m= ft This object falls 100 Meters (328 ft) in 4.4 seconds very nearly the same rate of fall as the examples above, further evidence of falling with nearly no resistance. source of the above freefall calculator: http://ww2.unime.it/weblab/mirror/ExplrSci/dswmedia/freefall.htm

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CD chart courtesy of NASA:
http://exploration.grc.nasa.gov/education/rocket/shaped.html
NASA has neglected to tell us what the frontal area is.

CD for a sphere has a huge range from .07 to .5
CD @ .07 dropped from 610 feet = TV of 290.274 ft/sec = fall time of 6.1599
CD @ .5 dropped from __610 feet = TV of 108.61 ft/sec_ = fall time of 7.3043 secs
CD @ .7 dropped from _610 feet = TV of 91.792 ft/s ___= fall time of 8.077 secs
Apples are not perfect spheres and so without wind tunnel testing one could estimate that .5 is closer to the CD of an apple than .07, or if we dropped an apple from 610 feet we could back our way in to the CD with algebra if we could observe the fall time. My guess is that the CD for an apple is more like .7 depending on the apple. Using a of .7 CD @ .7 dropped from __610 feet = TV of 91.792 ft/sec
Conclusion: Call in the Myth Busters

Freefall Of an Apple to Terminal Velocity, and then fall 610 feet (equal to WTC 7)
Weight of Apple .43 Pounds
Size of Apple is 2.75 x 3 inches = 0.0625 sq ft
Drag Coefficient = .5 (worst case aerodynamic for a sphere) Note that an apple is not a sphere
Drag Coefficient = .07 (best aerodynamic case for a sphere)
Source:
http://exploration.grc.nasa.gov/education/rocket/shaped.html
Terminal Velocity = 290.274 ft per second or 88.4755152 meters per second. Source:
http://exploration.grc.nasa.gov/education/rocket/termvr.html

 =========================== Using 0.07 CD and 610 Feet ===============
At time t = s after being dropped, the apple reaches terminal velocity and stops accelerating.
the speed is v_y = m/s = ft/s , = terminal velocity

The distance from the starting point will be
y = m= ft here shows you would need 1310 ft to accelerate to terminal velocity, so the apple would fall at freefall for 610 feet. which is seconds and never achieve terminal velocity.

=========================== Using .5 CD and 610 Feet================
After 3.3780 seconds, after travailing a distance of 183.4432 feet the apple reaches terminal velocity, then would travel another 426.5568 ft at108.61 ft/s = 3.9263 + initial time of 3.3780 = 7.3043, total distance of 610 feet

The National Institute of Standards and Technology (NIST) states the height of WTC7 as 610ft = 185.928m
http://wtc.nist.gov/progress_report_june04/appendixl.pdf

At time t = s after being dropped, the apple hits terminal velocity
the speed is v_y = m/s = ft/s , TV is achieved at after

The distance from the starting point will be
y = m= ft In the first 3.3780 seconds the apple would travel 183.4432 feet with 426.5568 feet to go @ 108.61 ft/s = 3.9263 secs + initial time of 3.3780 secs = 7.3043 secs

=========================== Using .7 CD and 610 Feet================

At time t = s after being dropped, the apple hits terminal velocity
the speed is v_y = m/s = ft/s , terminal velocity

The distance from the starting point will be
y = m= ft In the first 2.8549 seconds the apple would travel 131.0302 feet with 478.9698 feet to go @ 91.792 ft/s = 5.2179 secs + initial time of 2.8594 secs = 8.077 secs

http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html

Alfons v911t

Freefall

In the absence of frictional drag, an object near the surface of the earth will fall with the constant acceleration of gravity g. Position and speed at any time can be calculated from the motion equations.

Illustrated here is the situation where an object is released from rest. It's position and speed can be predicted for any time after that. Since all the quantities are directed downward, that direction is chosen as the positive direction in this case.

At time t = s after being dropped,
the speed is v_y = m/s = ft/s ,

The distance from the starting point will be
y = m= ft
Enter data in any box and click outside the box.

Above tells how far something would fall in ten seconds.
http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html
A very handy site for physics calculators

Below is the calculating for how fast something would fall from 417 Meters (the height of the WTC towers)

Freefall In the absence of frictional drag, an object near the surface of the earth will fall with the constant acceleration of gravity g. Position and speed at any time can be calculated from the motion equations. Illustrated here is the situation where an object is released from rest. It's position and speed can be predicted for any time after that. Since all the quantities are directed downward, that direction is chosen as the positive direction in this case. At time t = s after being dropped, the speed is vy = m/s = ft/s , The distance from the starting point will be y = m= ft Enter data in any box and click outside the box. You can play with this and other calculators @ the gsu site to prove the WTC towers fell too fast.  I put this here on the v911t for referenece to it, and to have it documented in case. ========== A study of top 15 floors of WTC Tower Fall Time in Atmosphere=============== After 27 seconds, after travailing a distance of 12, 401 feet the top 15 floors of the WTC towers reaches terminal velocity, but we dropped the top 15 floors from 1181 feet, so it never achieves Terminal Velocity, and falls at the rate of free fall. Freefall time from 1181 ft = 8.5710 371800000 lbs(Total Mass of a WTC tower) /110 = 3380000 x 15 = 50700000 lbs (Total Mass of the Top 15 floors) Mass of the Towers: http://forum.physorg.com/What-was-the-weight-of-a-WTC-Tower_4299.html Area Dimension of a WTC Tower is 208.005 ft at base is 43264 sf Dimension of Towers: http://en.structurae.de/structures/data/index.cfm?id=s0002118 Total Mass for top 15 floors 50700000 lbs Cross Section Area 43264 sf Drag Coefficient 1.28 Altitude 1181 Terminal Velocity 893 ft per second Terminal Velocity Calculator at NASA http://exploration.grc.nasa.gov/education/rocket/termvr.html   At time t = s after being dropped, the speed is vy = m/s = ft/s , The distance from the starting point will be y = m= ft The distance after being dropped is more than 1181 ft. , and will fall at the same rate as freefall http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html Freefall At time t = s after being dropped, the speed is vy = m/s = ft/s , The distance from the starting point will be y = m= ft Of interest here is the fact that atmosphere alone would stop the top 15 Floors from accelerating just from drag, if you dropped it from above 12, 401 feet. This begs the question, how much would it be slowed down if it had to fall through the rest of the WTC tower? The density of a WTC Tower is 371800000/59185152 = 6.28 lbs per cubic feet Air density is 0.07 lbs per cubic foot The density of the medium that a body falls through has an effect on it's Terminal Velocity. A body will fall in a liquid slower than it will through a gas, and even slower through something solid. When stuff gets in the way, it slows down the thing moving through it, the more stuff in the way, the slower the body goes, if it is not stopped entirely. A bullet goes through the air faster than it goes through a 10 foot thick brick wall, when you move something it takes work/energy to do it. In the case of things falling, we know exactly what that quanity of energy is. This refutes the "pancake theory" in a solid and provable way, based on the bedrocks of Newtonian physics. Things fall slower when they fall through denser medium.   ========== A study of Grand Piano Fall Time in Atmosphere=============== After 4 seconds, after travailing a distance of 257 feet the Grand Piano reaches terminal velocity, then falls 1111 at feet at 128.61 ft/s = 8.63 secs. + initial time of 4 seconds = 12.63 seconds total fall time from 1368 feet. At time t = s after being dropped, the speed is vy = m/s = ft/s , Terminal Velocity The distance from the starting point will be y = m= ft http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html Total Mass of Grand Piano 285 kg = 628.317 lb Cross Section Area 25.8215261675 sf Drag Coefficient 1.28 Altitude 1368 ft. Terminal Velocity 128.615 ft per second http://exploration.grc.nasa.gov/education/rocket/termvr.html The beautiful new GC1 combines the duplex scaling and rich tonal character of the coveted C1 grand with cost-saving advantages in materials and production to create an instrument that's both expressive and uncommonly affordable. Grand Piano Specifications: o Length: 161cm (5'3") o Width: 149cm – o Height: 101cm o Weight: 285k o Finished in Black Polyester 161 x 149 = 23989 sq cm http://www.pianoplus.co.uk/yamaha-piano/grands.html Piano Mass and dimensions in english and metric: 285 kg = 628.317 lb 161 cm = 5.28215 ft 149 cm = 4.88845 ft 4.88845 x 5.28215 = 25.8215261675 sq. ft. Dropped From 1368 feet Drag Coefficient = 1.28 (Flat Object CD 1.28 http://exploration.grc.nasa.gov/education/rocket/shaped.html Altitude = 417 meters = 1368 ft TV = 128.615 But those are the outside dimensions of the piano, pianos are not rectangular, but more like a right triangle, shaped in the most economical way to encase the stings. So they actual surface area could be more like 13 sf. rather than almost 26 sf. Then Terminal Velocity would be 181.889 ft/sec Example of the shape of a Piano: http://www.strand7.com/html/pianopaper.htm     After 5.65 seconds, after travailing a distance of 514.48 feet the Grand Piano reaches terminal velocity, then falls 853.52 at feet at 181.889 ft/sec = 4.69 secs. + initial time of 5.65 seconds = 10.34 seconds total fall time from 1368 feet. At time t = s after being dropped, the speed is vy = m/s = ft/s , The distance from the starting point will be y = m= ft Total Mass of Grand Piano 285 kg = 628.317 lb Cross Section Area 16 sf Drag Coefficient 1.28 Altitude 1368 ft. Terminal Velocity 181.889 ft/sec http://exploration.grc.nasa.gov/education/rocket/termvr.html So the fall time would likely be between 10.34 seconds and 12.63 seconds, depending on the shape, and the attitude the piano assumes as it falls.